Integrand size = 11, antiderivative size = 54 \[ \int \frac {\cot (x)}{a+b \cos (x)} \, dx=\frac {\log (1-\cos (x))}{2 (a+b)}+\frac {\log (1+\cos (x))}{2 (a-b)}-\frac {a \log (a+b \cos (x))}{a^2-b^2} \]
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Time = 0.11 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.182, Rules used = {2800, 815} \[ \int \frac {\cot (x)}{a+b \cos (x)} \, dx=-\frac {a \log (a+b \cos (x))}{a^2-b^2}+\frac {\log (1-\cos (x))}{2 (a+b)}+\frac {\log (\cos (x)+1)}{2 (a-b)} \]
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Rule 815
Rule 2800
Rubi steps \begin{align*} \text {integral}& = -\text {Subst}\left (\int \frac {x}{(a+x) \left (b^2-x^2\right )} \, dx,x,b \cos (x)\right ) \\ & = -\text {Subst}\left (\int \left (\frac {1}{2 (a+b) (b-x)}+\frac {a}{(a-b) (a+b) (a+x)}-\frac {1}{2 (a-b) (b+x)}\right ) \, dx,x,b \cos (x)\right ) \\ & = \frac {\log (1-\cos (x))}{2 (a+b)}+\frac {\log (1+\cos (x))}{2 (a-b)}-\frac {a \log (a+b \cos (x))}{a^2-b^2} \\ \end{align*}
Time = 0.06 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.93 \[ \int \frac {\cot (x)}{a+b \cos (x)} \, dx=\frac {\log \left (\cos \left (\frac {x}{2}\right )\right )}{a-b}-\frac {a \log (a+b \cos (x))}{a^2-b^2}+\frac {\log \left (\sin \left (\frac {x}{2}\right )\right )}{a+b} \]
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Time = 0.67 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.00
method | result | size |
default | \(\frac {\ln \left (\cos \left (x \right )-1\right )}{2 a +2 b}-\frac {a \ln \left (a +\cos \left (x \right ) b \right )}{\left (a +b \right ) \left (a -b \right )}+\frac {\ln \left (\cos \left (x \right )+1\right )}{2 a -2 b}\) | \(54\) |
risch | \(-\frac {i x}{a -b}-\frac {i x}{a +b}+\frac {2 i x a}{a^{2}-b^{2}}+\frac {\ln \left ({\mathrm e}^{i x}+1\right )}{a -b}+\frac {\ln \left ({\mathrm e}^{i x}-1\right )}{a +b}-\frac {a \ln \left ({\mathrm e}^{2 i x}+\frac {2 a \,{\mathrm e}^{i x}}{b}+1\right )}{a^{2}-b^{2}}\) | \(101\) |
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Time = 0.26 (sec) , antiderivative size = 53, normalized size of antiderivative = 0.98 \[ \int \frac {\cot (x)}{a+b \cos (x)} \, dx=-\frac {2 \, a \log \left (-b \cos \left (x\right ) - a\right ) - {\left (a + b\right )} \log \left (\frac {1}{2} \, \cos \left (x\right ) + \frac {1}{2}\right ) - {\left (a - b\right )} \log \left (-\frac {1}{2} \, \cos \left (x\right ) + \frac {1}{2}\right )}{2 \, {\left (a^{2} - b^{2}\right )}} \]
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\[ \int \frac {\cot (x)}{a+b \cos (x)} \, dx=\int \frac {\cot {\left (x \right )}}{a + b \cos {\left (x \right )}}\, dx \]
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Time = 0.22 (sec) , antiderivative size = 48, normalized size of antiderivative = 0.89 \[ \int \frac {\cot (x)}{a+b \cos (x)} \, dx=-\frac {a \log \left (b \cos \left (x\right ) + a\right )}{a^{2} - b^{2}} + \frac {\log \left (\cos \left (x\right ) + 1\right )}{2 \, {\left (a - b\right )}} + \frac {\log \left (\cos \left (x\right ) - 1\right )}{2 \, {\left (a + b\right )}} \]
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Time = 0.32 (sec) , antiderivative size = 54, normalized size of antiderivative = 1.00 \[ \int \frac {\cot (x)}{a+b \cos (x)} \, dx=-\frac {a b \log \left ({\left | b \cos \left (x\right ) + a \right |}\right )}{a^{2} b - b^{3}} + \frac {\log \left (\cos \left (x\right ) + 1\right )}{2 \, {\left (a - b\right )}} + \frac {\log \left (-\cos \left (x\right ) + 1\right )}{2 \, {\left (a + b\right )}} \]
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Time = 14.06 (sec) , antiderivative size = 47, normalized size of antiderivative = 0.87 \[ \int \frac {\cot (x)}{a+b \cos (x)} \, dx=\frac {\ln \left (\mathrm {tan}\left (\frac {x}{2}\right )\right )}{a+b}-\frac {a\,\ln \left (a+b+a\,{\mathrm {tan}\left (\frac {x}{2}\right )}^2-b\,{\mathrm {tan}\left (\frac {x}{2}\right )}^2\right )}{a^2-b^2} \]
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